Training courses

Kernel and Embedded Linux

Bootlin training courses

Embedded Linux, kernel,
Yocto Project, Buildroot, real-time,
graphics, boot time, debugging...

Bootlin logo

Elixir Cross Referencer

  1
  2
  3
  4
  5
  6
  7
  8
  9
 10
 11
 12
 13
 14
 15
 16
 17
 18
 19
 20
 21
 22
 23
 24
 25
 26
 27
 28
 29
 30
 31
 32
 33
 34
 35
 36
 37
 38
 39
 40
 41
 42
 43
 44
 45
 46
 47
 48
 49
 50
 51
 52
 53
 54
 55
 56
 57
 58
 59
 60
 61
 62
 63
 64
 65
 66
 67
 68
 69
 70
 71
 72
 73
 74
 75
 76
 77
 78
 79
 80
 81
 82
 83
 84
 85
 86
 87
 88
 89
 90
 91
 92
 93
 94
 95
 96
 97
 98
 99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
428
429
430
431
432
433
434
435
436
437
438
439
440
441
442
443
444
445
446
447
448
449
450
451
452
453
454
455
456
457
458
459
460
461
462
463
464
465
466
467
468
469
470
471
472
473
474
475
476
477
478
479
480
481
482
483
484
485
486
487
488
489
490
491
492
493
494
495
496
497
498
499
500
501
502
503
504
505
506
507
508
509
510
511
512
513
514
515
516
517
518
519
520
*	$NetBSD: bugfix.sa,v 1.3 1994/10/26 07:48:55 cgd Exp $

*	MOTOROLA MICROPROCESSOR & MEMORY TECHNOLOGY GROUP
*	M68000 Hi-Performance Microprocessor Division
*	M68040 Software Package 
*
*	M68040 Software Package Copyright (c) 1993, 1994 Motorola Inc.
*	All rights reserved.
*
*	THE SOFTWARE is provided on an "AS IS" basis and without warranty.
*	To the maximum extent permitted by applicable law,
*	MOTOROLA DISCLAIMS ALL WARRANTIES WHETHER EXPRESS OR IMPLIED,
*	INCLUDING IMPLIED WARRANTIES OF MERCHANTABILITY OR FITNESS FOR A
*	PARTICULAR PURPOSE and any warranty against infringement with
*	regard to the SOFTWARE (INCLUDING ANY MODIFIED VERSIONS THEREOF)
*	and any accompanying written materials. 
*
*	To the maximum extent permitted by applicable law,
*	IN NO EVENT SHALL MOTOROLA BE LIABLE FOR ANY DAMAGES WHATSOEVER
*	(INCLUDING WITHOUT LIMITATION, DAMAGES FOR LOSS OF BUSINESS
*	PROFITS, BUSINESS INTERRUPTION, LOSS OF BUSINESS INFORMATION, OR
*	OTHER PECUNIARY LOSS) ARISING OF THE USE OR INABILITY TO USE THE
*	SOFTWARE.  Motorola assumes no responsibility for the maintenance
*	and support of the SOFTWARE.  
*
*	You are hereby granted a copyright license to use, modify, and
*	distribute the SOFTWARE so long as this entire notice is retained
*	without alteration in any modified and/or redistributed versions,
*	and that such modified versions are clearly identified as such.
*	No licenses are granted by implication, estoppel or otherwise
*	under any patents or trademarks of Motorola, Inc.

*
*	bugfix.sa 3.2 1/31/91
*
*
*	This file contains workarounds for bugs in the 040
*	relating to the Floating-Point Software Package (FPSP)
*
*	Fixes for bugs: 1238
*
*	Bug: 1238 
*
*
*    /* The following dirty_bit clear should be left in
*     * the handler permanently to improve throughput.
*     * The dirty_bits are located at bits [23:16] in
*     * longword $08 in the busy frame $4x60.  Bit 16
*     * corresponds to FP0, bit 17 corresponds to FP1,
*     * and so on.
*     */
*    if  (E3_exception_just_serviced)   {
*         dirty_bit[cmdreg3b[9:7]] = 0;
*         }
*
*    if  (fsave_format_version != $40)  {goto NOFIX}
*
*    if !(E3_exception_just_serviced)   {goto NOFIX}
*    if  (cupc == 0000000)              {goto NOFIX}
*    if  ((cmdreg1b[15:13] != 000) &&
*         (cmdreg1b[15:10] != 010001))  {goto NOFIX}
*    if (((cmdreg1b[15:13] != 000) || ((cmdreg1b[12:10] != cmdreg2b[9:7]) &&
*				      (cmdreg1b[12:10] != cmdreg3b[9:7]))  ) &&
*	 ((cmdreg1b[ 9: 7] != cmdreg2b[9:7]) &&
*	  (cmdreg1b[ 9: 7] != cmdreg3b[9:7])) )  {goto NOFIX}
*
*    /* Note: for 6d43b or 8d43b, you may want to add the following code
*     * to get better coverage.  (If you do not insert this code, the part
*     * won't lock up; it will simply get the wrong answer.)
*     * Do NOT insert this code for 10d43b or later parts.
*     *
*     *  if (fpiarcu == integer stack return address) {
*     *       cupc = 0000000;
*     *       goto NOFIX;
*     *       }
*     */
*
*    if (cmdreg1b[15:13] != 000)   {goto FIX_OPCLASS2}
*    FIX_OPCLASS0:
*    if (((cmdreg1b[12:10] == cmdreg2b[9:7]) ||
*	 (cmdreg1b[ 9: 7] == cmdreg2b[9:7])) &&
*	(cmdreg1b[12:10] != cmdreg3b[9:7]) &&
*	(cmdreg1b[ 9: 7] != cmdreg3b[9:7]))  {  /* xu conflict only */
*	/* We execute the following code if there is an
*	   xu conflict and NOT an nu conflict */
*
*	/* first save some values on the fsave frame */
*	stag_temp     = STAG[fsave_frame];
*	cmdreg1b_temp = CMDREG1B[fsave_frame];
*	dtag_temp     = DTAG[fsave_frame];
*	ete15_temp    = ETE15[fsave_frame];
*
*	CUPC[fsave_frame] = 0000000;
*	FRESTORE
*	FSAVE
*
*	/* If the xu instruction is exceptional, we punt.
*	 * Otherwise, we would have to include OVFL/UNFL handler
*	 * code here to get the correct answer.
*	 */
*	if (fsave_frame_format == $4060) {goto KILL_PROCESS}
*
*	fsave_frame = /* build a long frame of all zeros */
*	fsave_frame_format = $4060;  /* label it as long frame */
*
*	/* load it with the temps we saved */
*	STAG[fsave_frame]     =  stag_temp;
*	CMDREG1B[fsave_frame] =  cmdreg1b_temp;
*	DTAG[fsave_frame]     =  dtag_temp;
*	ETE15[fsave_frame]    =  ete15_temp;
*
*	/* Make sure that the cmdreg3b dest reg is not going to
*	 * be destroyed by a FMOVEM at the end of all this code.
*	 * If it is, you should move the current value of the reg
*	 * onto the stack so that the reg will loaded with that value.
*	 */
*
*	/* All done.  Proceed with the code below */
*    }
*
*    etemp  = FP_reg_[cmdreg1b[12:10]];
*    ete15  = ~ete14;
*    cmdreg1b[15:10] = 010010;
*    clear(bug_flag_procIDxxxx);
*    FRESTORE and return;
*
*
*    FIX_OPCLASS2:
*    if ((cmdreg1b[9:7] == cmdreg2b[9:7]) &&
*	(cmdreg1b[9:7] != cmdreg3b[9:7]))  {  /* xu conflict only */
*	/* We execute the following code if there is an
*	   xu conflict and NOT an nu conflict */
*
*	/* first save some values on the fsave frame */
*	stag_temp     = STAG[fsave_frame];
*	cmdreg1b_temp = CMDREG1B[fsave_frame];
*	dtag_temp     = DTAG[fsave_frame];
*	ete15_temp    = ETE15[fsave_frame];
*	etemp_temp    = ETEMP[fsave_frame];
*
*	CUPC[fsave_frame] = 0000000;
*	FRESTORE
*	FSAVE
*
*
*	/* If the xu instruction is exceptional, we punt.
*	 * Otherwise, we would have to include OVFL/UNFL handler
*	 * code here to get the correct answer.
*	 */
*	if (fsave_frame_format == $4060) {goto KILL_PROCESS}
*
*	fsave_frame = /* build a long frame of all zeros */
*	fsave_frame_format = $4060;  /* label it as long frame */
*
*	/* load it with the temps we saved */
*	STAG[fsave_frame]     =  stag_temp;
*	CMDREG1B[fsave_frame] =  cmdreg1b_temp;
*	DTAG[fsave_frame]     =  dtag_temp;
*	ETE15[fsave_frame]    =  ete15_temp;
*	ETEMP[fsave_frame]    =  etemp_temp;
*
*	/* Make sure that the cmdreg3b dest reg is not going to
*	 * be destroyed by a FMOVEM at the end of all this code.
*	 * If it is, you should move the current value of the reg
*	 * onto the stack so that the reg will loaded with that value.
*	 */
*
*	/* All done.  Proceed with the code below */
*    }
*
*    if (etemp_exponent == min_sgl)   etemp_exponent = min_dbl;
*    if (etemp_exponent == max_sgl)   etemp_exponent = max_dbl;
*    cmdreg1b[15:10] = 010101;
*    clear(bug_flag_procIDxxxx);
*    FRESTORE and return;
*
*
*    NOFIX:
*    clear(bug_flag_procIDxxxx);
*    FRESTORE and return;
*

BUGFIX    IDNT    2,1 Motorola 040 Floating Point Software Package

	section	8

	include	fpsp.h

	xref	fpsp_fmt_error

	xdef	b1238_fix
b1238_fix:
*
* This code is entered only on completion of the handling of an 
* nu-generated ovfl, unfl, or inex exception.  If the version 
* number of the fsave is not $40, this handler is not necessary.
* Simply branch to fix_done and exit normally.
*
	cmpi.b	#VER_40,4(a7)
	bne.w	fix_done
*
* Test for cu_savepc equal to zero.  If not, this is not a bug
* #1238 case.
*
	move.b	CU_SAVEPC(a6),d0
	andi.b	#$FE,d0
	beq 	fix_done	;if zero, this is not bug #1238

*
* Test the register conflict aspect.  If opclass0, check for
* cu src equal to xu dest or equal to nu dest.  If so, go to 
* op0.  Else, or if opclass2, check for cu dest equal to
* xu dest or equal to nu dest.  If so, go to tst_opcl.  Else,
* exit, it is not the bug case.
*
* Check for opclass 0.  If not, go and check for opclass 2 and sgl.
*
	move.w	CMDREG1B(a6),d0
	andi.w	#$E000,d0		;strip all but opclass
	bne	op2sgl			;not opclass 0, check op2
*
* Check for cu and nu register conflict.  If one exists, this takes
* priority over a cu and xu conflict. 
*
	bfextu	CMDREG1B(a6){3:3},d0	;get 1st src 
	bfextu	CMDREG3B(a6){6:3},d1	;get 3rd dest
	cmp.b	d0,d1
	beq.b	op0			;if equal, continue bugfix
*
* Check for cu dest equal to nu dest.  If so, go and fix the 
* bug condition.  Otherwise, exit.
*
	bfextu	CMDREG1B(a6){6:3},d0	;get 1st dest 
	cmp.b	d0,d1			;cmp 1st dest with 3rd dest
	beq.b	op0			;if equal, continue bugfix
*
* Check for cu and xu register conflict.
*
	bfextu	CMDREG2B(a6){6:3},d1	;get 2nd dest
	cmp.b	d0,d1			;cmp 1st dest with 2nd dest
	beq.b	op0_xu			;if equal, continue bugfix
	bfextu	CMDREG1B(a6){3:3},d0	;get 1st src 
	cmp.b	d0,d1			;cmp 1st src with 2nd dest
	beq	op0_xu
	bne	fix_done		;if the reg checks fail, exit
*
* We have the opclass 0 situation.
*
op0:
	bfextu	CMDREG1B(a6){3:3},d0	;get source register no
	move.l	#7,d1
	sub.l	d0,d1
	clr.l	d0
	bset.l	d1,d0
	fmovem.x d0,ETEMP(a6)		;load source to ETEMP

	move.b	#$12,d0
	bfins	d0,CMDREG1B(a6){0:6}	;opclass 2, extended
*
*	Set ETEMP exponent bit 15 as the opposite of ete14
*
	btst	#6,ETEMP_EX(a6)		;check etemp exponent bit 14
	beq	setete15
	bclr	#etemp15_bit,STAG(a6)
	bra	finish
setete15:
	bset	#etemp15_bit,STAG(a6)
	bra	finish

*
* We have the case in which a conflict exists between the cu src or
* dest and the dest of the xu.  We must clear the instruction in 
* the cu and restore the state, allowing the instruction in the
* xu to complete.  Remember, the instruction in the nu
* was exceptional, and was completed by the appropriate handler.
* If the result of the xu instruction is not exceptional, we can
* restore the instruction from the cu to the frame and continue
* processing the original exception.  If the result is also
* exceptional, we choose to kill the process.
*
*	Items saved from the stack:
*	
*		$3c stag     - L_SCR1
*		$40 cmdreg1b - L_SCR2
*		$44 dtag     - L_SCR3
*
* The cu savepc is set to zero, and the frame is restored to the
* fpu.
*
op0_xu:
	move.l	STAG(a6),L_SCR1(a6)	
	move.l	CMDREG1B(a6),L_SCR2(a6)	
	move.l	DTAG(a6),L_SCR3(a6)
	andi.l	#$e0000000,L_SCR3(a6)
	clr.b	CU_SAVEPC(a6)
	move.l	(a7)+,d1		;save return address from bsr
	frestore (a7)+
	fsave	-(a7)
*
* Check if the instruction which just completed was exceptional.
* 
	cmp.w	#$4060,(a7)
	beq	op0_xb
* 
* It is necessary to isolate the result of the instruction in the
* xu if it is to fp0 - fp3 and write that value to the USER_FPn
* locations on the stack.  The correct destination register is in 
* cmdreg2b.
*
	bfextu	CMDREG2B(a6){6:3},d0	;get dest register no
	cmpi.l	#3,d0
	bgt.b	op0_xi
	beq.b	op0_fp3
	cmpi.l	#1,d0
	blt.b	op0_fp0
	beq.b	op0_fp1
op0_fp2:
	fmovem.x fp2,USER_FP2(a6)
	bra.b	op0_xi
op0_fp1:
	fmovem.x fp1,USER_FP1(a6)
	bra.b	op0_xi
op0_fp0:
	fmovem.x fp0,USER_FP0(a6)
	bra.b	op0_xi
op0_fp3:
	fmovem.x fp3,USER_FP3(a6)
*
* The frame returned is idle.  We must build a busy frame to hold
* the cu state information and setup etemp.
*
op0_xi:
	move.l	#22,d0		;clear 23 lwords
	clr.l	(a7)
op0_loop:
	clr.l	-(a7)
	dbf	d0,op0_loop
	move.l	#$40600000,-(a7)
	move.l	L_SCR1(a6),STAG(a6)
	move.l	L_SCR2(a6),CMDREG1B(a6)
	move.l	L_SCR3(a6),DTAG(a6)
	move.b	#$6,CU_SAVEPC(a6)
	move.l	d1,-(a7)		;return bsr return address
	bfextu	CMDREG1B(a6){3:3},d0	;get source register no
	move.l	#7,d1
	sub.l	d0,d1
	clr.l	d0
	bset.l	d1,d0
	fmovem.x d0,ETEMP(a6)		;load source to ETEMP

	move.b	#$12,d0
	bfins	d0,CMDREG1B(a6){0:6}	;opclass 2, extended
*
*	Set ETEMP exponent bit 15 as the opposite of ete14
*
	btst	#6,ETEMP_EX(a6)		;check etemp exponent bit 14
	beq	op0_sete15
	bclr	#etemp15_bit,STAG(a6)
	bra	finish
op0_sete15:
	bset	#etemp15_bit,STAG(a6)
	bra	finish

*
* The frame returned is busy.  It is not possible to reconstruct
* the code sequence to allow completion.  We will jump to 
* fpsp_fmt_error and allow the kernel to kill the process.
*
op0_xb:
	jmp	fpsp_fmt_error

*
* Check for opclass 2 and single size.  If not both, exit.
*
op2sgl:
	move.w	CMDREG1B(a6),d0
	andi.w	#$FC00,d0		;strip all but opclass and size
	cmpi.w	#$4400,d0		;test for opclass 2 and size=sgl
	bne	fix_done		;if not, it is not bug 1238
*
* Check for cu dest equal to nu dest or equal to xu dest, with 
* a cu and nu conflict taking priority an nu conflict.  If either,
* go and fix the bug condition.  Otherwise, exit.
*
	bfextu	CMDREG1B(a6){6:3},d0	;get 1st dest 
	bfextu	CMDREG3B(a6){6:3},d1	;get 3rd dest
	cmp.b	d0,d1			;cmp 1st dest with 3rd dest
	beq	op2_com			;if equal, continue bugfix
	bfextu	CMDREG2B(a6){6:3},d1	;get 2nd dest 
	cmp.b	d0,d1			;cmp 1st dest with 2nd dest
	bne	fix_done		;if the reg checks fail, exit
*
* We have the case in which a conflict exists between the cu src or
* dest and the dest of the xu.  We must clear the instruction in 
* the cu and restore the state, allowing the instruction in the
* xu to complete.  Remember, the instruction in the nu
* was exceptional, and was completed by the appropriate handler.
* If the result of the xu instruction is not exceptional, we can
* restore the instruction from the cu to the frame and continue
* processing the original exception.  If the result is also
* exceptional, we choose to kill the process.
*
*	Items saved from the stack:
*	
*		$3c stag     - L_SCR1
*		$40 cmdreg1b - L_SCR2
*		$44 dtag     - L_SCR3
*		etemp        - FP_SCR2
*
* The cu savepc is set to zero, and the frame is restored to the
* fpu.
*
op2_xu:
	move.l	STAG(a6),L_SCR1(a6)	
	move.l	CMDREG1B(a6),L_SCR2(a6)	
	move.l	DTAG(a6),L_SCR3(a6)	
	andi.l	#$e0000000,L_SCR3(a6)
	clr.b	CU_SAVEPC(a6)
	move.l	ETEMP(a6),FP_SCR2(a6)
	move.l	ETEMP_HI(a6),FP_SCR2+4(a6)
	move.l	ETEMP_LO(a6),FP_SCR2+8(a6)
	move.l	(a7)+,d1		;save return address from bsr
	frestore (a7)+
	fsave	-(a7)
*
* Check if the instruction which just completed was exceptional.
* 
	cmp.w	#$4060,(a7)
	beq	op2_xb
* 
* It is necessary to isolate the result of the instruction in the
* xu if it is to fp0 - fp3 and write that value to the USER_FPn
* locations on the stack.  The correct destination register is in 
* cmdreg2b.
*
	bfextu	CMDREG2B(a6){6:3},d0	;get dest register no
	cmpi.l	#3,d0
	bgt.b	op2_xi
	beq.b	op2_fp3
	cmpi.l	#1,d0
	blt.b	op2_fp0
	beq.b	op2_fp1
op2_fp2:
	fmovem.x fp2,USER_FP2(a6)
	bra.b	op2_xi
op2_fp1:
	fmovem.x fp1,USER_FP1(a6)
	bra.b	op2_xi
op2_fp0:
	fmovem.x fp0,USER_FP0(a6)
	bra.b	op2_xi
op2_fp3:
	fmovem.x fp3,USER_FP3(a6)
*
* The frame returned is idle.  We must build a busy frame to hold
* the cu state information and fix up etemp.
*
op2_xi:
	move.l	#22,d0		;clear 23 lwords
	clr.l	(a7)
op2_loop:
	clr.l	-(a7)
	dbf	d0,op2_loop
	move.l	#$40600000,-(a7)
	move.l	L_SCR1(a6),STAG(a6)
	move.l	L_SCR2(a6),CMDREG1B(a6)
	move.l	L_SCR3(a6),DTAG(a6)
	move.b	#$6,CU_SAVEPC(a6)
	move.l	FP_SCR2(a6),ETEMP(a6)
	move.l	FP_SCR2+4(a6),ETEMP_HI(a6)
	move.l	FP_SCR2+8(a6),ETEMP_LO(a6)
	move.l	d1,-(a7)
	bra	op2_com

*
* We have the opclass 2 single source situation.
*
op2_com:
	move.b	#$15,d0
	bfins	d0,CMDREG1B(a6){0:6}	;opclass 2, double

	cmp.w	#$407F,ETEMP_EX(a6)	;single +max
	bne.b	case2
	move.w	#$43FF,ETEMP_EX(a6)	;to double +max
	bra	finish
case2:	
	cmp.w	#$C07F,ETEMP_EX(a6)	;single -max
	bne.b	case3
	move.w	#$C3FF,ETEMP_EX(a6)	;to double -max
	bra	finish
case3:	
	cmp.w	#$3F80,ETEMP_EX(a6)	;single +min
	bne.b	case4
	move.w	#$3C00,ETEMP_EX(a6)	;to double +min
	bra	finish
case4:
	cmp.w	#$BF80,ETEMP_EX(a6)	;single -min
	bne	fix_done
	move.w	#$BC00,ETEMP_EX(a6)	;to double -min
	bra	finish
*
* The frame returned is busy.  It is not possible to reconstruct
* the code sequence to allow completion.  fpsp_fmt_error causes
* an fline illegal instruction to be executed.
*
* You should replace the jump to fpsp_fmt_error with a jump
* to the entry point used to kill a process. 
*
op2_xb:
	jmp	fpsp_fmt_error

*
* Enter here if the case is not of the situations affected by
* bug #1238, or if the fix is completed, and exit.
*
finish:
fix_done:
	rts

	end